Easy To Fix Error C2668 Ambiguous Solution

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    Here are some simple steps that can help you fix the ambiguous error c2668 problem. The conversion of a created with constant 0 is ambiguous given that conversion is required for both long and void *. To fix this error, for good results, pass 0 for the exact type of the parameter for which it is used. In this case, no conversion is required.

    Try to create the below provider code from the example in the manual.I am using Visual Business 2008.

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  • The compiler doesn’t know what to do:

    error c2668 ambiguous

      1> ------ with rebuild Everything started: Project: fig21.40, config: Win32 Debug ------1> Removing and temporarily exiting downloads for project 'fig21.40', config 'Debug | Win32 '1> Compile ...1> fig21_40.cpp1> c:  users  ocuk  documents  c ++  chapter 21  fig21.40  fig21.40  fig21_40.cpp (27) Error: C2668: 'sqrt': unsafe overloaded function call1> c:  Program Files (x86)  Microsoft Visual Professional Studio 9.0  vc  include  math.h (581): could be 'long double sqrt (long double)'.1> c:  Program Files (x86)  Microsoft Visual Suite 9.0  vc  include  math.h (533): or 'float sqrt (float)'1> c:  program paperwork (x86)  microsoft visual studio 9.0  vc  include  math.h (128): otherwise 'double sqrt (double)'1> trying to match argument list '(const int)'1> The build file was saved as' file: // c:  Users  ocuk  Documents  C ++  Chapter 21  fig21.40  fig21.40  Debug  BuildLog.htm ".1> fig21.40. ... ... Error (s), 1 0 Warning (s)========== Rebuild all: 0 successful, 1 failed, 8 ignored ========== 

    error c2668 ambiguous

      // Fig. 21:40: fig21_40.cpp// Use a real set of bits to demonstrate the Eratosthenes sieve#include using std :: cin;with std :: cost;with std :: endl;#include with std :: setw;#include  // Define  In Bit Mode#include // sqrt prototypeint main ()size of an integer const = 1024;integer value;std :: sieve  bitset;sie.flip ();// Screening Eratosthenseint finalBit = sqrt filter (.) size () + 1;for (int i = 2; i > value;while (value! means -1)    if (sieve [value])        cout << value << "can be a simple numberscrap  n ";    different        cout << value << "is not a large number  n";    cout << " nEnter each value between 2 and 1023 positive (-1 at the end):";    cin >> value;// ends duringReturns 0; 

    There are actually answers to this question here:

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    Errore C2668 Ambiguo
    Erro C2668 Ambiguo
    오류 C2668 모호함
    Erreur C2668 Ambigue
    Blad C2668 Niejednoznaczny
    Fel C2668 Tvetydigt
    Oshibka C2668 Neodnoznachnaya
    Error C2668 Ambiguo
    Fout C2668 Dubbelzinnig
    Fehler C2668 Mehrdeutig

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