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Here are some simple steps that can help you fix the ambiguous error c2668 problem. The conversion of a created with constant 0 is ambiguous given that conversion is required for both long and void *. To fix this error, for good results, pass 0 for the exact type of the parameter for which it is used. In this case, no conversion is required.
Try to create the below provider code from the example in the manual.I am using Visual Business 2008.
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The compiler doesn’t know what to do:
1> ------ with rebuild Everything started: Project: fig21.40, config: Win32 Debug ------1> Removing and temporarily exiting downloads for project 'fig21.40', config 'Debug | Win32 '1> Compile ...1> fig21_40.cpp1> c: users ocuk documents c ++ chapter 21 fig21.40 fig21.40 fig21_40.cpp (27) Error: C2668: 'sqrt': unsafe overloaded function call1> c: Program Files (x86) Microsoft Visual Professional Studio 9.0 vc include math.h (581): could be 'long double sqrt (long double)'.1> c: Program Files (x86) Microsoft Visual Suite 9.0 vc include math.h (533): or 'float sqrt (float)'1> c: program paperwork (x86) microsoft visual studio 9.0 vc include math.h (128): otherwise 'double sqrt (double)'1> trying to match argument list '(const int)'1> The build file was saved as' file: // c: Users ocuk Documents C ++ Chapter 21 fig21.40 fig21.40 Debug BuildLog.htm ".1> fig21.40. ... ... Error (s), 1 0 Warning (s)========== Rebuild all: 0 successful, 1 failed, 8 ignored ==========
// Fig. 21:40: fig21_40.cpp// Use a real set of bits to demonstrate the Eratosthenes sieve#include using std :: cin;with std :: cost;with std :: endl;#include with std :: setw;#include // Define In Bit Mode#include // sqrt prototypeint main ()size of an integer const = 1024;integer value;std :: sieve bitset;sie.flip ();// Screening Eratosthenseint finalBit = sqrt filter (.) size () + 1;for (int i = 2; i > value;while (value! means -1) if (sieve [value]) cout << value << "can be a simple numberscrap n "; different cout << value << "is not a large number n"; cout << " nEnter each value between 2 and 1023 positive (-1 at the end):"; cin >> value;// ends duringReturns 0;
There are actually answers to this question here:
Keep your PC safe and secure with this freeErrore C2668 Ambiguo
Erro C2668 Ambiguo
오류 C2668 모호함
Erreur C2668 Ambigue
Blad C2668 Niejednoznaczny
Fel C2668 Tvetydigt
Oshibka C2668 Neodnoznachnaya
Error C2668 Ambiguo
Fout C2668 Dubbelzinnig
Fehler C2668 Mehrdeutig
